Why can't gulp find the task?

Question

JavaScript

var gulp = require('gulp');
var sass = require('gulp-sass');
var browserSync = require('browser-sync');


gulp.task('sass', function(){
  return gulp.src('src/scss/**/*.scss')
    .pipe(sass()) // Конвертируем Sass в CSS с помощью gulp-sass
    .pipe(gulp.dest('dist/css')
    .pipe(browserSync.reload({
        stream: true
    })))
});

gulp.task('watch', ['browserSync'], function (){
    gulp.watch('app/scss/**/*.scss', ['sass']); 
    gulp.watch('src/*.html', browserSync.reload);
    gulp.watch('src/js/**/*.js', browserSync.reload);
  })

gulp.task('browserSync', function() {
  browserSync({
    server: {
      baseDir: 'src'
    },
  })
})

Answer 1

Here is a detailed video of what has changed in the syntax and how to fix it - link