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droidex2017-04-30 15:32:23
openvpn
droidex, 2017-04-30 15:32:23

Vpn through a proxy - what does the provider see?

When we connect to the Internet through vpn, then for the provider all data looks encrypted.
That is, he sees only ip:port and how much where when the bytes are merged.
But if I have this chain: socks5 proxy -> vpn ?
That is, the connection to the VPN goes through a proxy (socks-proxy ip in the openvpn config)
After all, the proxy, as you know, does not have encryption. What does the provider see in this case?
Do I understand correctly that he sees all the traffic? Or is the proxy just a transit? And is it normal to use such a scheme?
ps proxy and vpn are up on different servers :)

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4 answer(s)
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Eugene_Eesti, 2017-04-30
@Eugene_Eesti

Anonymity is a multiple sequence of actions.
What you use will not give you even 5% anonymity.
If you plan to make the task much more difficult, then start with Qubes .

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15432, 2017-04-30
@15432

The provider sees the same encrypted traffic going to the VPN server through the proxy server.
The proxy only forwards the data without changing it.

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droidex, 2017-04-30
@droidex

But in this case, the provider sees that I use vpn or not? Indeed, in fact, only the first connection is visible to him - a proxy, and then it is no longer visible, as I understand it?

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CityCat4, 2017-04-30
@CityCat4

OMG, when will we start writing questions from the offender model? To the provider itself, your connection is up to the current lamp - at least ten VPNs in a chain line up. You need to start with who (what) you are protecting yourself from. It's one thing when you want to watch porn at work (and then your violator is the administrator of the office, well, the Security Service, if any), it's another thing if you want to get into politics (and then your violator is the state). Do I need to explain that they have slightly different capabilities? The state, having seen an incomprehensible proxy with SOCKS, will not figure out what the proxy itself is - it will come to you ... and you yourself will tell everything.
It's well written here

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