How to parse string in XSLT transformation?

Question

HTML

Good afternoon! There is an XML document and it is necessary to make its XSLT transformation. The trouble is that the string must be parsed into table cells - one letter in one cell, in order to form a semblance of a printing form, that is

<Документ КНД="1111053" ДатаДок="16.01.2012" КодНО="7601">

should look something like this

<tr>
<td>КНД</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>1</td>
<td>0</td>
<td>5</td>
<td>3</td>
</tr>

Answer 1

You can implement this using substring .
XML document:

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="docstyle.xsl"?>

<Документы>
    <Документ КНД='1102345' ДатаДок="16.01.2012" КодНО="7601" />
    <Документ КНД='1111053' ДатаДок="12.12.2016" КодНО="7601" />
</Документы>

XSL Schema (docstyle.xsl)

<?xml version="1.0" encoding="UTF-8" ?>

<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"  xmlns="http://www.w3.org/1999/xhtml">
    <xsl:output method="xml" indent="yes" doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN" doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"/>

    <xsl:template match="Документы/Документ">
        <tr>
            <td><xsl:value-of select="@ДатаДок"/></td>
            <td><xsl:value-of select='substring(@КНД,1,1)'/></td>
            <td><xsl:value-of select='substring(@КНД,2,1)'/></td>
            <td><xsl:value-of select='substring(@КНД,3,1)'/></td>
            <td><xsl:value-of select='substring(@КНД,4,1)'/></td>
            <td><xsl:value-of select='substring(@КНД,5,1)'/></td>
            <td><xsl:value-of select='substring(@КНД,6,1)'/></td>
        </tr>
    </xsl:template>
</xsl:stylesheet>