How to decode panic?

Question

macOS

Hello. Please help me understand what is encrypted in this bug report:

panic(cpu 1 caller 0xfffffff021f614fc): macOS watchdog detected
Debugger message: panic
Memory ID: 0x6
OS version: 17P6610
macOS version: 19G2021
Kernel version: Darwin Kernel Version 19.6.0: Thu Jun 18 20:30:46 PDT 2020; root:xnu-6153.145.1~1/RELEASE_ARM64_T8010
Kernel UUID: B4EDD42A-0513-3B38-A0EF-ED8AF599F183
iBoot version: iBoot-5540.140.12
secure boot?: YES
x86 EFI Boot State: 0x16
x86 System State: 0x0
x86 Power State: 0x0
x86 Shutdown Cause: 0x0
x86 Previous Power Transitions: 0x10001000100
PCIeUp link state: 0x89473614
Paniclog version: 13
Kernel slide:     0x0000000019f24000
Kernel text base: 0xfffffff020f28000
mach_absolute_time: 0x84715d9a84
Epoch Time:        sec       usec
  Boot    : 0x5f5936dc 0x0002cf5d
  Sleep   : 0x5f5a0b82 0x0001a562
  Wake    : 0x5f5a2236 0x00075f8b
  Calendar: 0x5f5a407c 0x000e019d

Panicked task 0xffffffe000203600: 3049 pages, 220 threads: pid 0: kernel_task
Panicked thread: 0xffffffe000602f88, backtrace: 0xffffffe0152fb4b0, tid: 341
      lr: 0xfffffff0217ec860  fp: 0xffffffe0152fb4f0
      lr: 0xfffffff0217ec6bc  fp: 0xffffffe0152fb560
      lr: 0xfffffff021907770  fp: 0xffffffe0152fb610
      lr: 0xfffffff021db95d8  fp: 0xffffffe0152fb620
      lr: 0xfffffff0217ec024  fp: 0xffffffe0152fb990
      lr: 0xfffffff0217ec37c  fp: 0xffffffe0152fb9e0
      lr: 0xfffffff022626974  fp: 0xffffffe0152fba00
      lr: 0xfffffff021f614fc  fp: 0xffffffe0152fba30
      lr: 0xfffffff021f5292c  fp: 0xffffffe0152fbaa0
      lr: 0xfffffff021f54854  fp: 0xffffffe0152fbb50
      lr: 0xfffffff021f52064  fp: 0xffffffe0152fbbe0
      lr: 0xfffffff021f194c8  fp: 0xffffffe0152fbc10
      lr: 0xfffffff021d26b14  fp: 0xffffffe0152fbc50
      lr: 0xfffffff021d26398  fp: 0xffffffe0152fbc90
      lr: 0xfffffff021dc4514  fp: 0x0000000000000000