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How to crimp an RJ-45 + socket correctly?
There are a lot of articles on the Internet on how to make a socket for a provider or crimp a cable on both sides, but there is no clarifying information (well, I didn’t see at least, since I’m doing it for the second time in my life) in order to do the following: I want to make a bunch of socket and cable from it, which will be plugged into my router to get 1Gbps in the next room.
There is a type A and B connection diagram on the socket, do I understand correctly that I then need to simply compress the cable on the other side according to any of the options in principle (relative to the one I choose on the A + A or B + B socket). For some reason, it seemed to me that in the case from the router to the computer, the colors should be added sequentially and not jump in the center (so where yellow jumps blue in the center or green, depending on the scheme).
So
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> do I understand correctly what I need then, according to the scheme, to simply compress the cable on the other side according to any of the options in principle (relative to the one I choose on the A + A or B + B socket)
correctly.
> the colors must be stacked sequentially and not jump in the center
incorrectly.
The cable is routed according to the template according to which it was made.
It is done like this - 2 cm of the braid is removed and the pairs are bred in a cross, as they are laid in the cable. The pair that is opposite the blue one will cover it in the wiring, then the side pairs are laid out next to it.
Now, in most cases, the cable "B" is made, but sometimes the cable "A" also comes across.
And I also came across a couple of times the cables of the "drunk Chinese", where multi-colored and one-color retinues or retinues are not in color.
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