How to correctly shove all my asynchronous Promise.all functions?

Question

JavaScript

Tell me please. How to do it correctly so that until the block of code number 1 is executed, action number 2 is not performed

export const getAllQues = (collection) => {
  return async (dispatch) => {
    const db = firebase.firestore();
    const settings = { timestampsInSnapshots: true };
    db.settings(settings);
    const allquestions = {};
    const docRef = db.collection(collection);
    try {
      const doc = await docRef.get();
      doc.forEach(async (item) => {
        const array = [];
        const ref = db.collection(collection).doc(item.id).collection('questions');
        const total = await ref.get();
        total.forEach(async (interval) => {
          array.push(interval.data());
        });
        allquestions[item.id] = array;
      });
    } catch (e) {
      throw e;
    }
    const result = allquestions;
    dispatch(allQues(result));
    return result;
  };
};

Answer 1

await Promise.all(doc.map(item => (async(item) { /* ... */ })(item)))

doc.map(item => ...)