How to compare values ​​in output lines and conditionally execute a script?

Question

linux

I display the temperature values ​​​​of the processor with the command:
sensors | grep "Core *" | awk '{print int($3)}'
At the output:

37
39
38
36

How to compare them with the value "60" and if at least one value is greater than 60, then execute a certain sh-script?

Answer 1

For example, so

sensors | grep "Core *" | awk '{print int($3)}' | xargs -L 1 -i bash -c "[ {} -gt 37 ] && echo '{} больше 37'"

And with the script call it will be like this

sensors | grep "Core *" | awk '{print int($3)}' | xargs -L 1 -i bash -c "[ {} -gt 60 ] && ./too_hot.sh'"