How to get the "tail" of a file starting from a line containing a certain substring?

Question

linux

preferably with standard grep, awk etc...

Answer 1

For example, awk:

/нужная_строка/ { found = 1 }

found { print }

Answer 2

man grep:

Context Line Control
-A NUM, --after-context=NUM
Print NUM lines of trailing context after matching lines. Places a line containing a group separator (--) between contiguous groups of matches.
With the -o or --only-matching option, this has no effect and a warning is given.
-B NUM, --before-context=NUM
Print NUM lines of leading context before matching lines. Places a line containing a group separator (--) between contiguous groups of matches.
With the -o or --only-matching option, this has no effect and a warning is given.
-C NUM, -NUM, --context=NUM
Print NUM lines of output context. Places a line containing a group separator (--) between contiguous groups of matches. With the -o or
--only-matching option, this has no effect and a warning is given.

I hope by "tail" you don't mean an indefinite (and theoretically unlimited) number of lines from the desired line to the end of the file?