Has the network 172.16.10.0/23 subnetted correctly with a capacity of 80 hosts?

Question

Computer networks

How many networks with a capacity of 80 hosts can the 172.16.10.0 /23 network be divided into?

Answer 1

Wrong! You can see what address ranges are offered to you, they have a maximum of 16 addresses in each subnet. And you need 80
. it is impossible to get exactly 80 addresses in a subnet, then you need to take the minimum allowable number greater than 80 - this is 128. For 128 nodes, the subnet mask will be /25 (255.255.255.128).
From the original range with /23 mask, only 4 subnets with /25 mask can
be distinguished :

Answer 2

Networks cannot be subnetted with 80 hosts.
Only a multiple of 4 - that is, 4 - 8 - 16 - 32 - 64 - 128
If you want one network - then 128 minimum, if two - 64 + 32.
This is if you need 80 hosts (minus the network ID and ip broadcast)

Answer 3

To zero :)
It is impossible to create a network with a capacity that is not equal to a power of two. You can split the network into subnets with a capacity of 128 addresses - in real life, such a solution would fail, but with a noticeable overhead, I would try to cut the networks down to 64 in order to use addresses more densely.
But you have a learning task with a trick :) You are tritely tested for knowledge of network theory and it seems that you did not pass the test ...
JFYI: IMHO, a network engineer must know the table of powers of two by heart