Why is the array not formed in foreach?

Question

PHP

Hello.
Why is the array not formed?

$outbad = array();
$outgood = array();
foreach((array)$emails as $key=>$e){
if (да){
$outgood[] .= $emailadress['dfgh'] . " хороший адрес"; // и такой вариант
} else{
$outbad[] .= array($emailadress . " плохой адрес"); // и такой вариант
}
echo $outgood;
echo $outbad;

The cycle sorts out something of its own, this is not the point. The bottom line is that the array is not formed. Failure in different ways.
And tried another option.

$outbad[] = array($emailadress . " плохой адрес");
$outgood[] = $emailadress['dfgh'] . " хороший адрес";

Answer 1

And emails - what is it?

$ems = array('abc', 'def');
$outbad = array();
$outgood = array();

foreach ($ems as $val) {
  if (true) {
    $outgood[] = $val.' - OK';    
  } else {
    $outbad[] = $val.' - FAIL';   
  }
}
echo $outgood;
echo $outbad;

Answer 2

from the ceiling because you take variables) you are in a cycle, use either a key or a variable that distributes $key $e. push or so $outgood[] = $e or array_push($outgood, $e);

foreach($emails as $key=>$e){
if (да) {
    $outgood[] = $e . " хороший адрес";
} else {
    $outbad[] = [$key . " плохой адрес"]; 
}