Why doesn't IF checking work in arduino?

Question

Arduino

I want to write a check: if the data from the sensor is equal to the previous data, then the LED is on without blinking and an error message is displayed, but no matter how I tried to do it, nothing changed: when the module was turned off, the message was not sent, the LED blinked, and I went into a binge . Here is the code:

void setup() {
 
 while (!pressure.begin()){
    Serial.println("Modules init fail\nRetrying");
    analogWrite(10, 150);
    delay(1000);
 }
 analogWrite(10, LOW);
 Serial.println("Modules init success");

 
 Serial.println("BMP180's t°; BMP180's mBar; time");
}
 
void loop() {
  char status;
  double p180T,p180P,p0,a,b20t,p180T_if;

  analogWrite(10, 150);
  status = pressure.startTemperature();          // Считывание показания
  if(status!=0){                                 // Если значение status не 0, выполняем следующию команду.
     delay(status);                              // Ждем    
     status = pressure.getTemperature(p180T);}   // Полученые показания, сохраняем в переменную p180T
     
  status = pressure.startPressure(3);            // Считывание показания
  if(status!=0){                                 // Если значение status не 0, выполняем следующию команду.
    delay(status);                               // Ждем
    status = pressure.getPressure(p180P,p180T);} // Полученные показания, сохраняем в переменную p180P

 if (p180T != (p180T_if,10)){
   p180T_if = p180T;
   Serial.println();
   Serial.print(p180T,10); //max: 19
   Serial.print("; ");
   Serial.print(p180P,10); //max: 14
   Serial.print("; ");
   Serial.print(p180T_if);
   Serial.print("; ");
   Serial.print(p180T);
   Serial.print("; ");
  
   analogWrite(10, LOW);
   delay(1000);}
 else{
   analogWrite(10, 150);
   Serial.print("Pressure module disconnected");
   delay(1000);
 }
}

I cut it down a bit and removed everything off topic, if you need the full code - write.
Thanks in advance!

Answer 1

if (p180T != (p180T_if,10))

This place must have meant something else. Now it's written here if (p180T != 10).

Answer 2

Declare the status as Then it will be declared once and will be stored permanently at the beginning of RAM