Why does bash change a variable?

Question

linux

Help to deal with the script:
There is a condition where a name is assigned to the variable view1

# Check MY-SERVER
if ffmpeg -f libndi_newtek -find_sources 1 -i dummy 2>&1 | grep 'MY-SERVER (1)'
then
        view1=" -f libndi_newtek -thread_queue_size 1024 -i 'MY-SERVER (1)'"
        echo "MY-SERVER (1) is running! Everything is fine..."

Next, I try to use the value of a variable in a script:

# Run FFMPEG
ffmpeg -hwaccel cuvid $view1 $view2 $view3 
...
...
...

FFMPEG returns error because variables are not expanded correctly:

-f libndi_newtek -thread_queue_size 1024 -i ''\''MY-SERVER' '(1)'\'''

And I need it to turn out exactly as specified in the variable:

-f libndi_newtek -thread_queue_size 1024 -i 'MY-SERVER (1)'

Can't figure out how to achieve this?
Thanks

Answer 1

And so
ffmpeg -hwaccel cuvid "$view1" "$view2" "$view3"

Answer 2

Try this
so?
or so

IFS=$'\n'
view1=" -f libndi_newtek -thread_queue_size 1024 -i 'MY-SERVER (1)'"