Why do molecules heat up with the forces of the pendant?

Question

Mathematics

Hello, I have a question more in physics than in programming.
If we consider molecules in a closed space, then 3 main forces will act on them:

• Orientation forces
  
• Dispersive attraction
  
• Induction attraction
  

All these forces can be described by the van der Waals equation, which has the form
In turn, the graph of these interactions has an approximate form

: line.

When this line is reached, the molecule with a high degree of probability will already change the direction of motion.
Then the minimum approach radius will be equal to the value (the line marked in blue).

Let's agree that on the radius scale this value (minimum approach distance) will be equal to 10 conventional units.
Then the system does not warm up and is in a stable state.

It is necessary to make a digression, that water is modeled with the transition of hydrogen to another molecule, and thus the Coulomb forces are formed between them, since the molecules acquire charges of different signs. Water becomes H30 AND HO.

Molecules donate a proton when they come close enough together.
Thus, in addition to the previously considered force, there is also a pendant force, which on the graph looks like this:

Thus, the attraction between molecules of different charges will appear sharply, and if we take into account that they have become opposite in the vicinity of each other, then more interactions will occur with each other friend. (I don’t know how I explained my idea, in my opinion it’s bad).
Then taking into account that the molecules have inertia at a distance marked in green they acquire this inertia (forces directed towards each other).

Thus, they pass this peak and, having some inertia, rush towards each other, thereby overcoming the values ​​​​of 10 conventional units established earlier (marked with a blue line, the new minimum limit, the green one is the old one)

Suppose that now this value has become equal to 8 units of distance.


However, we had previously ruled that molecules transfer their charge when they are at a certain distance of approach, and since this pair of molecules are at an even smaller distance, the probability of charge transfer is inversely greater than with other molecules. Thus, they break their connection and become neutral.
However, their normal distance in this position has already become 8 units. Then the repulsive force acts on them more, thereby they scatter with greater inertia, which leads to heating of the system.
Drawn in brown is the emerging force, which turns into an increase in the energy of the system, thereby and the speed of their movement.


How to make sure that the system does not heat up? What am I not considering or could this be a normal situation?

For example, I wrote an illustration of these molecules .

How to start:

• Run the .exe
  
• Click on "Settings."
  
• Then click on the "Create."
  
• In the pop-up window, click on the left side of this form
  

PS I'm not a programmer, so if there are bugs, then I'm sorry. You can close the program only by reloading it and causing an error. I don't know how else.
PS If necessary, then the script code .

Thank you in advance for your response.

Answer 1

How to make sure that the system does not heat up? What am I not considering or could this be a normal situation?

You do not take into account that immediately after the transition of the hydrogen nucleus to another molecule, the Coulomb force already begins to act, it reduces the speed of the expansion of molecules, and a decrease in the speed of molecules is cooling. Everything, according to the law of conservation of energy, did not decrease or increase anything, only the energy passed into another form, and then returned to its previous form.

Answer 2

the body falling on the tail is sent to * th (C)