N
N
Nikolay Zhivotenko2014-12-08 18:34:19
Electronics
Nikolay Zhivotenko, 2014-12-08 18:34:19

Which solid state DC relay to choose?

Good day, there is a rather informal task, namely the mechanical switching of the HDD power supply at the moment when the PC is turned off.
Available: two HDDs, switch, PSU with molex 4-pin connectors.
Why you need it: Steampunk PC modding is being done.
What is the idea:
There are 2 HDDs in the PC, when the PC is turned off, you can flip the switch to the ON / OFF position, while the circuit going to the relay closes.
When the circuit is closed (ON position) and the PC is turned on, the control voltage of 5V from the 4-pin PSU connector is supplied to the relay, and as a result, 5V and 12V power is supplied to HDD 2, but there is no power to HDD 1.
When the circuit is open (OFF position), no control voltage is applied to the relay, and therefore only HDD 1 is powered.
The essence of the question is the following, how to choose the right solid state relay with a constant control voltage of 5V and a switched constant voltage from 5V to 12V?
Is the K293LP7R optoelectronic relay suitable in this case?
After all, the problem lies in the auto-lock of the button / switch, suddenly the user will feel like clicking the switch when the PC is working.
Or maybe it is better to use circuits on triacs / thyristors?
I am attaching a picture from paint, sorry for the simplicity of the scheme. The blue and purple arrows here schematically show how the current flows. Blue when switch is ON, purple when OFF.
3bd71bb0d0c54e6b8e5607526fe59a55.png
PS: For those who are especially meticulous, I will immediately answer the question: "Why not programmatic power switching, for example from the BIOS?", Because I'm not interested in this path.

Answer the question

In order to leave comments, you need to log in

1 answer(s)
O
Ocelot, 2014-12-09
@niko_zvt

The easiest way, probably, to do on electromagnetic relays:
Switch S1 selects which HDD should turn on. Depending on its state, when power is applied, one of the relays K1 or K2 is activated, becomes self-locking and simultaneously breaks the S1 circuit. After that, clicking the switch is already useless - the second relay will not work. When the power is turned off, the system is reset.
Capacitors C1, C2 are needed in order for the auto-blocking to work: the opening contact works a few milliseconds earlier than the closing one. Diodes VD1, VD2 protect capacitors from self-induction EMF.

Didn't find what you were looking for?

Ask your question

Ask a Question

731 491 924 answers to any question