What is the error (why is the function exiting 5 and not 7)?

Question

Python

x=5
def funA(x,y):
x=7
return x
funA(x,4)
print x

Answer 1

Read about references, objects, variable scope, and how to pass parameters to a function.
What we see in the code: we
created an object with the value "5" and assigned a reference to it to the variable "x"

def funA(x,y):
        x=7
        return x

created a function with two parameters
in the body of the function introduced a local variable "x"
as a result returned a local variable
called the function with parameters 5 and 4
printed a non-local variable "x"
And now the answer to your question:
At the exit from the function just 7

>>> x=5

>>> def funA(x,y):
      x = 7
      return x

>>> funA(x,4)
7

And what you took for the "exit" of the function is just the variable "x", which has no idea about your function, what is happening inside it and what is returned

Answer 2

or
or

def funA(y):
    global x
    x = 7
    return y