Overwrite Gulp file?

Question

JavaScript

There is a task that generates Sprites, but each time it is called, not only new pictures are added to the existing sprite, but in general everything that is in the folder (i.e. pictures are duplicated). How can I delete a sprite each time so that it is generated from scratch or somehow not duplicate pictures?

gulp.task('sprite', function () {
  	let spriteData = gulp.src('src/assets/img/sprite/*.*').pipe(spritesmith({
      imgName: 'sprite.png',
      imgPath: '../img/sprite/sprite.png',
      cssName: '../../css/sprite.scss',
      algorithm: 'binary-tree',
      padding: 5,
      cssFormat: 'scss'
  }));
  return spriteData.pipe(gulp.dest('src/assets/img/sprite/'));
});

Answer 1

'src/assets/img/sprite/*.*'- that's why everyone is taken. Take only what you need