Is there a difference between a buffer overflow in VirtualBox and real hardware?

Question

virtual box

Do not run the suggested files if you do not understand all the consequences of your actions

The question is this. Is there a difference between a buffer overflow in, for example, VirtualBox and real hardware?
What would not pour water test.
1) There is an old exploit for winrar 3.60 securityvulns.ru/Gnews880.html
There is a poc.rar code.
2) Old winrar 3.60
expirebox.com/download/7323278aeb93af568dbe2e05a87...
We check the rhinestone in virustotal :)
3) You need windows 7/8/10 x86 on real hardware. VirtualBox - I have it myself.
Actually, by opening this poc.rar with an old rar, does your console program load? Or WerFault falls out.
UPD
Host Windows XP3 32bit DEP
Guest Windows 7_1 32bit DEP
VirtualBox 5.0
Test.exe listing below. The string secret will only be on buffer overflow.
_____________________DEP on_________________DEP off__
Host(poc.rar)............not working............working
Host(test.exe). .........doesn't work...................
guestbook works (poc.rar)........doesn't work... ............ not working???
guestbook(test.exe)........ working??? ............works
Installing/removing Guest Additions has no effect.
-------------------------------------------------- --------------------------------

#include "stdio.h"
#include "string.h"
#pragma comment(linker, "/BASE:0x10400000")


char *esp="\xff\xd4";


int foo(char *in)
{
char temp[100];
memcpy(temp,in,strlen(in));
return 0;
}



int n()
{
printf("\n");
printf("secret");
return 0;
}



int main()
{
char temp[1024];
long p=(long)esp;
long f=(long)n;
memset(temp,0x90,sizeof(temp));
memcpy(temp+104,&p,sizeof(p));

memcpy(temp+104+sizeof(p),"\xb8",1);
memcpy(temp+104+sizeof(p)+1,&f,sizeof(f));
memcpy(temp+104+sizeof(p)+1+sizeof(f),"\xff\xd0",2);

printf("call esp: %p",p);

foo(temp);
return 0;
}