Is it possible to use open('file','r').read() in python?

Question

Python

The question is perhaps a little silly, but: today, instead of the usual

f = open('file','r')
text = f.read()
f.close()

I tried it and I was wondering if it is possible to do this and does the file close on its own? Or maybe it's all the same somehow manually close it?
text = open('file','r').read()

Answer 1

You can do this: In this case, everything will close correctly. In general, you should try to use modern methods of working with files and paths, rather than prehistoric ones. By the way, you can make a self-closing reader yourself:
content = pathlib.Path('file').read_bytes()

def readfromfile(filename, mode='t'):
    assert mode in {'b', 't'}
    with open(filename, mode=mode) as f:
        return f.read()

But why, when there is a wonderful pathlib in the third python out of the box?
Well, I’ll also add about the non-closing of files.
In production code that plans to live for a long time, of course, you need to close everything correctly, but if you have a small one-time script that does not open millions of files, then it is quite possible to score on closing it. When the process (interpreter) terminates, all of its handles will be freed.

Answer 2

Closes "automatically" only when using the context manager

with open('file','r') as f:
  text = f.read()

As soon as the code leaves this with block, the file will be closed.