If a RAR archive is allocated 5% for recovery, then the probability of its recovery is 5%?

Question

rar

If not, what is the point of these percentages?

Answer 1

The RAR format may contain special data that contains information for restoring the file.

File recovery information can contain up to 524,288 sectors. In case of file corruption, WinRAR is able to recover 512 bytes of data using each sector. This indicator may change downwards if there has been multiple damage to the file.

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Answer 2

no, this means that you can throw out any 5% of this file and everything will be restored. Read more about error-correcting coding on the wiki.

Answer 3

here is a ratio

Answer 4

No, you'll excuse me, but even as a child I understood such things.

Answer 5

More likely 5% * compression ratio, although I was not interested

Answer 6

IMHO: with an extremely low probability of getting a file damaged by 5% when transferred over the Internet or on modern hard drives, it is irrational to allocate 5% of traffic for information for recovery. the probability of a case in which its use will be required and will help, as far as I understand, is negligible. The recovery record was relevant at the time of the development of the RAR algorithm (although it is probably different in its current version) - at the time of floppy disks and BBS.

Answer 7

as far as I remember the encoding course, depending on the encoding method, the message is divided into blocks of length M bytes for which N bytes of the security code are calculated. Depending on the type of code, it can recover single, double, etc. Errors ibenno in the block of the code instead of in the message entirely. That is, you can’t just throw out 5 archive projects, it must be less than or equal to the maximum number of errors per message block - just the sum of all N to the sum of all M is 5 percent