How to write a condition in a bat file?

Question

cmd/bat

I am running a bat file.
If an error occurs during execution, I throw it on the error label .
ping -invalid-arg || goto error
But how to make a condition: if there is no error at this moment, transfer it to the next label?

those. I need a solution
if the file gives an error when executed, throw it on the error label .
if the file does not give an error, either we transfer it to the next label or, even more simply, we continue execution.
The main task is to catch the error and throw it on the label for further work of the file.

Answer 1

I found a solution!
We check for errors, if there are any, then ERRORLEVEL 1 will work if there is no ERRORLEVEL 0 .
Accordingly, we assign different labels for each of them.

if ERRORLEVEL 1 goto answer1
if ERRORLEVEL 0 goto answer0

Answer 2

Add the next line.

ping -invalid-arg || goto error
goto next

Answer 3

ping -invalid-arg && goto GOOD || goto BAD
And besides, for some internal commands, this is the only way, since they do not set ERRORLEVEL , but the success of their execution is checked using &&/ ||.