How to take only one value from the json response and return it to the page?

Question

PHP

I have this code:

<?php

$p_url = $_POST['p_url'];
$url = 'https://site.ru/?url='.$p_url.'';

$result = file_get_contents($url);
echo $result;

?>

I turn to the Api of the page, in response to the main page, a lot of values ​​\u200b\u200bcome, but I only need to take this:
"media_id": "это нужно выводить",
How to do this?

Answer 1

Like this:

<?php

$p_url = $_POST['p_url'];
$url = 'https://site.ru/?url='.$p_url.'';

$result = file_get_contents($url);
echo json_decode($result, true)['media_id'];