How to start a python process in linux?

Question

linux

Good day, it became necessary to run the script in a function using

subprocess.Popen("path/python.py %s" % stats.id,
                             shell=True, stdout=subprocess.PIPE)

However, in Linux there is such a problem, until the script finishes its work, the function hangs.
I would like to run the script in the background.
Z.s. python 2.7

Answer 1

try this:
subprocess.Popen("path/python.py %s & " % stats.id,
shell=True, stdout=subprocess.PIPE)

Answer 2

Excellent! Do not take it for impudence, but where can I read more about such nuances?

Answer 3

subprocess.Popen(["path/python.py", stats.id])