How to send a socket the property value of all other sockets?

Question

Layout

I'm picking Node,js, I've reached the Socket.IO library. I've run into a problem that I haven't been able to find a solution to yet.
The server has the following lines:

io.on('connection', function(socket){
    socket.session = {};
    socket.session.address = socket.handshake.address;           

    function setName(name){
        if(name != undefined && name != ''){
            socket.session.userName = name;
            socket.broadcast.emit('newUser', socket.session.userName);
            socket.emit('userName', socket.session.userName);
            logger.info('User '+socket.session.userName+' join from IP: '+socket.session.address);
        }
        else
            socket.emit('setName');
    }
    setName(null);
    socket.on('setName', function(name){
        if(name.length > 0)
            setName(name);
        else
            socket.emit('setName');
    });

...
}

I wondered how, with a successfully given login (socket.session.userName), send the names of all other sockets to the socket (socket.session.userName of all other sockets)?

Answer 1

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    <div class="tab-item" id="tab1">Content 1</div>
    <div class="tab-item" id="tab2">Content 2</div>
</div>
<div class="tab-links">
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        <li>
      <a href="#tab1">Tab 1</a>
  </li>
  <li>
            <a href="#tab2">Tab 2</a>
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    </ul>
</div>

var tabContainers = $('.tab-item-wrapper .tab-item');

tabContainers.hide().filter(':first').show();
  
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  $('.tab-links a').removeClass('selected');
  $(this).addClass('selected');
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}).filter(':first').click();

Well, you’ll probably add the styles yourself, right? :-)