How to replace file paths with gulp?

Question

gulp.js

gulp.task('styles', function () {
    return gulp.src(['source/styles/scss/**/*.scss', 'source/include/**/*.scss'])
        .pipe(sass())
        .pipe(remember('styles'))
        .pipe(concat('style.css'))
    
        .pipe(ftp({
            host: '',
            user: '',
            pass: '',
            remotePath: ''
        }));
});

Such a situation, I collect scss on the local, the file has such a path

src: local("Blogger_Sans"), url(../fonts/FiraSansBold/FiraSansBold.ttf);

and on the machine I copy it all to ftp, and there wordpress and the style.css file lies at the root of the theme. And there will already be such a way

src: local("Blogger_Sans"), url(/fonts/FiraSansBold/FiraSansBold.ttf);

Maybe something can be written in the task to change the paths on the fly as I need.

Answer 1

https://www.npmjs.com/package/gulp-replace
I think the point is clear