How to remove unnecessary code from returned ajax html?

Question

PHP

For example, it returns an html code in which there is an input, but I don’t need it, how can I remove the input from this code?

Answer 1

str_replace

Answer 2

Insert the resulting html into a temporary hidden div, carry out all the manipulations you need with it, and then transfer the resulting dom to the place you need and finally delete the temporary div

Answer 3

strreplace = function (search, replace, str){
return str.split(search).join(replace);
};

Answer 4

jquery $(input).remove()