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How to properly divide the network?
This is the test that I am doing.
The network requires 4 VLANs. There is a main network 192.168.48.0/20 which needs to be divided into additional ones. Addresses are assigned in the order of the VLANs listed below:
VLAN ID/ NAME/ Size
11 / group1 / 50 devices
12 / group2 / 150 devices
13 / group3 / 2000 devices
14 / group4 / 600 devices
If you divide the network into subnets, and in order. it turns out that for the first group, for example, the network will be 192.168.48.0/24, for the second 192.168.49.0/24, for the third 192.168.56.0/21, and for the fourth there are no more addresses left.
Am I misunderstanding something in the assignment? And how to do it right?
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Start with big chunks:
==== For 2000 devices ==========
Network: 192.168.48.0/21
HostMin: 192.168.48.1
HostMax: 192.168.55.254
Hosts/Net: 2046
==== For 600 devices ==========
Network: 192.168.56.0/22
HostMin: 192.168.56.1
HostMax: 192.168.59.254
Hosts/Net: 1022
==============
And you have there are still 4 free networks on /24:
192.168.60.0/24
192.168.61.0/24
192.168.62.0/24
192.168.63.0/24
If you really need to assign addresses in order, then no way. Because the third group of 2000 hosts "fits" only in the /21 mask, which is half of the available mask and should go either at the beginning (192.168.48.0/21) or at the end (192.168.56.0/21), but not in the middle.
11 - 192.168.60.0/26
12 - 192.168.61.0/24
13 - 192.168.48.0/21
14 - 192.168.56.0/22
You are cutting wrong. The /20 grid holds 4096 addresses. First allocate the longest mesh under vlan13 (2000 hosts) /21, descending further. For vlan 11, in your case, a /26 mesh for 64 addresses is enough.
See 192.168.48.0/20 these are 4094 hosts 192.168.48.1-192.168.63.254
It can be broken into the following networks, according to the conditions of your problem:
192.168.48.0/26 (62 hosts)
192.168.48.64/24 (254 hosts)
192.168.49.0/ 21 (2046 hosts)
192.168.56.0/22 (1022 hosts)
If I remember correctly.
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