How to pass an arbitrary number of arguments to a function parameter?

Question

JavaScript

Good afternoon!
There is a function, the first parameter is an array, the second is a string. If the string value is in the array, it is removed from the array. But if there are more than 1 rows in the second parameter, the function processes only the last value.
I tried wrapping the filter in a for (i=0; ifunction destroyer(arr, args) {
var x = arr.filter(function(values){
return values ​​!== args;
});
return x;
}
var z = destroyer( ["tree", "hamburger", 53], "tree", 53)
;

Answer 1

function delStr(ar){
  var strOf = [].slice.call(arguments, 1);
  return ar.filter(function(e){
     return strOf.indexOf(e) < 0;
  });
}

delStr(["a", "b", "c", "d"], "c", "d"); //["a", "b"]