How to parse the log?

Question

bash

Hello. Help parse the log
There is a status log from openVPN like this.

ivanov.as,IP_addres,56924339,46404603,Thu Apr 16 07:20:32
2020
16 08:08:04 2020

Bash or regular expressions need to read the presence of a user for example ivanov.as every minute and write to another log like ivanov.as 1, after a minute read the log again and if the user is there, increase the counter by one

PS I understand that the solution can be a crutch, I don’t know how else to take into account the connection time of users to the OpenVPN server.

Thanks in advance to everyone who replied.

Answer 1

cut -d, -f2 111.txt
where the -dseparator is a ","
-fcolumn it remains for you to cut it as you need here you will receive online all the lines about this comrade, then you can count them
tail -f /var/log/syslog | grep -o "ivanov.as"

tail -f /var/log/syslog  |  grep -o "ivanov.as" | wc -l > ivanov.sa

but here it's better to take the whole file

cat  /var/log/syslog  |  grep -o "ivanov.as" | wc -l > ivanov.sa

well, if you need to compile a list of users and their number of mentions, then it’s different here.
But it was not in TK;)