How to output only 1 line after grep -A 1 matches?

Question

linux

How to output only 1 line after grep -A 1 matches?

Given test.txt:
ABCD
777

Example:
grep -A 1 'ABCD' test.txt

Output:
ABCD
777

Required output:
777

Answer 1

you can remove it with the second grep filter:
grep -A 1 'ABCD' test.txt | grep -v 'ABCD'
7777
naturally, if the second line (which we want to save) also contains ABCD, then you need to modify the second grep to find something that is not there ... but the principle remains the same

Answer 2

you can without too much witchcraft)))
grep -A 1 'ABCD' test.txt | tail -n 1
BUT if there are several lines with 'ABCD'??? :(

Answer 3

Try like this:
sed -n '/ABCD/{x;n;p;D}' test.txt

Answer 4

It is possible like this:

$ awk '{line = $0}; END {print line}' text.txt

вывод в констоль:
777