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Here it is necessary to apply de Morgan's rules (twice), bracketing, associativity and the law of exclusion of the middle.
!a!b + !ab!c + !(a + !c)
!a!b + !ab!c + !ac
!a(!b + b!c + c)
Inside brackets:
!b + b!c + c = b!c + (!b + c) = b!c + !(b!c) = 1
Only !a remains
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