How to make a callback function in php like in Laravel?

Question

PHP

Hello, I want to create an MVC app, I take an example from Laravel, there is a function

Route::get('/', function () {
    return view('welcome');
});
//или 
Route::get('/', '[email protected]');

and I did this:

//index.php

require "Debug.php";

use app\core\Router;
spl_autoload_register(function($class){
    $path = str_replace('\\','/',$class).'.php';
    if(file_exists($path)){
        require $path;
    }
});
session_start();

require 'app/core/web.php';
$router = new Router;

//Router.php
namespace app\core;

class Router{

    public static $routes = [];

    public function __construct(){
        $uri = $_SERVER['REQUEST_URI'];
        if(array_search($uri,self::$routes)){
            echo $uri;
        }else{
            header('Location:/beejee/404');
        }
    }
    static public function get($url,$param){
        echo $param;
        self::$routes[] = '/beejee'.$url;
    }
    static public function post($url){
        self::$routes[] = '/beejee'.$url;
    }
    static public function put($url){
        self::$routes[] = '/beejee'.$url;
    }
    static public function delete($url){
        self::$routes[] = '/beejee'.$url;
    }
}

//web.php
use app\core\Router;

Router::get('/',function(){
    return 'home';
});
Router::get('/admin',function(){
    return 'asd';
});
Router::get('404');

How can I implement it so that it is like in laravel?

Answer 1

public function __construct(){
        $uri_path = $_SERVER['REQUEST_URI']; // Тут нужно как-то получить PATH часть из ссылки, можно через parse_url

        if(isset(self::$routes[$uri_path]) && is_callable(self::$routes[$uri_path])){
            return call_user_func( self::$routes[$uri_path] ); // Вызов callback функции 
        }else{
            header('Location:/beejee/404');
        }
}
static public function get( $url, $callback ){
self::$routes[$url] = $callback;
}