How to get process name?

Question

linux

How can I return only the process name?
For example: ps -u userReturns a table.
I only need the process name to display it on the site.
For the output I use a PHP script:

$cmd = "ps -u s" . $server['sid'] . ";";
      ssh::exec_cmd($cmd);
      $data = trim(ssh::get_output());
      $data = explode("\n", $data);
      $d['proc'] = 0;
      foreach($data as $key => $value)
        {
        $d['proc'] = $value;
        }

Maybe you can immediately get the name or filter it somehow in the loop?
Who knows, tell me.

Answer 1

ps -p $$ -o comm -h
look at the process -p $$ (pid of the current process), display only the column with the command (-o comm), hide the header line (-h)

Answer 2

We do not read mana, we parse through awk, yeah.
With sorting:

ps -u юзер -o comm --sort=-comm --no-headers | head -n 1

Answer 3

I asked myself, I will answer.
So far this is how it turned out:
ps -u юзер | awk '{print $4}' | sort -rn | head -1

Answer 4

Your process? Then php.net/manual/ru/function.getmypid.php