How to get only some elements of an array using destructuring?

Question

JavaScript

An array comes into the function parameter

[(не нужное), (не нужное), (НУЖНОЕ №1), (не нужное), (НУЖНОЕ №2)]

I wrote the function very nicely,

function someFunction([null, null, null, id, null, status]) {
    ...
}

But writes Duplicate parameters are invalid.
How can an array be destructured to get only the 3rd and 5th elements?

Answer 1

Instead of unnecessary elements, do not specify anything: Or, you can destructure the array as a regular object:
function someFunction([ ,,, id,, status ]) {
function someFunction({ 3: id, 5: status }) {