How to get link in HTML via dlango?

Question

Django

How can I get the link of the image I want? There is a model:

class Tour(models.Model):
    name = models.CharField('Место',max_length=50)
    bg = models.ImageField('Фон', upload_to='media/')

There is a view:

def tour(request):
    places = Tour.objects.all()
    context = {'places': places}
    return render(request, 'tour/index.html', context)

I need to substitute the image I need in HTML:
url("{{ bgs.bg.url }}")
For example, now I need 1, I will go to another page, there will be a third one, and so on.
When I go through the pages, the link does not change, because pictures in the layout on one page, they just change