How to fix an error in ajax request?

Question

Yii

Hello.
There is an ActiveForm in which the radio is in the modal window, but the problem is that the values ​​​​are not saved to the database, it shows alert('fail');

<?php $form = ActiveForm::begin([
    'id' => 'formTest',
    'type' => ActiveForm::TYPE_HORIZONTAL,
    'formConfig' => ['labelSpan' => 3, 'deviceSize' => ActiveForm::SIZE_SMALL]
]);

$list = [0 => 'one', 1 => 'two', 2 => 'three'];
?>

<?= $form->field($model, 'name')->radioList($list)->label(false); ?>
<div class="form-group">
    <?= \yii\helpers\Html::submitButton('<i class="glyphicon glyphicon-ok"></i> Ok', ['class' => 'btn btn-primary']) ?>
</div>
<?php ActiveForm::end(); ?>

js

$js = <<< JS

$(document).ready(function() {
    
    $('form#formTest').on('beforeSubmit', function () {
        var data = $(this).serialize();
        $.ajax({
            type: 'post',
            url: 'message',
            data: data,
            
            error: function() {
                console.log('error');
            },
            
            success: function(){
                console.log(data);
            },
        })
        .done(function(data) {
           if(data.success) {
              alert('success');
           } else {
              alert('fail');
           }
        });

        return false;
    });
});

JS;

Controller

public function actionMessage()
{
    $model = new Post();

    if(\Yii::$app->request->isAjax) {
        if ($model->load(Yii::$app->request->post()) && $model->validate()) {
            $model->save();
        }
    }

    return $this->renderAjax('message', [
        'model'=>$model,
    ]);
}

Answer 1

This condition is probably never met in your code by if(data.success) since you don't return anything from the controller except the form. You need to return a positive response upon successful saving of the model

Answer 2

I redid it a little, now it works, but the button is essentially not needed, when switching radioboxes, the value is immediately saved to the database. How can I make it save after clicking submit? What to fix?
Now it works without js.
view

<?php $form = ActiveForm::begin([
    'id' => 'formTest',
    'method' => 'POST',
    'enableAjaxValidation' => true,
    'type' => ActiveForm::TYPE_HORIZONTAL,
    'formConfig' => [
        'showErrors' => true,
        'labelSpan' => 1,
        'deviceSize' => ActiveForm::SIZE_SMALL,
    ]
]);
?>

<?= $form->field($model, 'Name')->radioList($list)->label(false); ?>

<?php ActiveForm::end(); ?>

Controller

public function actionMessage($id)
{
    $model = Orders::findOne($id);

    if (Yii::$app->request->isAjax && $model->load(Yii::$app->request->post())) {

        if ($model->save()) {
            return $this->renderAjax('message', [
                'model'=>$model,
            ]);
        } else {
            Yii::$app->response->format = Response::FORMAT_JSON;
            return ActiveForm::validate($model);
        }
    }

    return $this->renderAjax('message', [
        'model'=>$model,
    ]);
}