How to find and replace multiple occurrences in text with one script?

Question

JavaScript

there is such a construction that allows you to find and replace a certain occurrence in html - a word or a sentence - with another one on the fly.

$("body").children().each(function() {
    $(this).html($(this).html().replace(/old text/g,"new text"));
  });

Now, if such substitutions need to be made about a dozen - i.e. there are 10 occurrences that need to be replaced with 10 new ones, while of course you need a clear correspondence, what will change to what.
How to solve this problem in less than 10 times to write this construction?

Answer 1

const replacements = [
  [ 'вот это надо заменить', 'вот на это' ],
  [ 'а это заменить', 'на вот это' ],
];

$elements.html((i, html) => {
  return replacements.reduce((acc, n) => acc.replace(RegExp(n[0], 'g'), n[1]), html);
});

Answer 2

The easiest thing is not to sweat.
Something like this, I wrote without testing, but I hope the idea is understandable

const replacePairs= {'было1': 'стало1', 'было2': 'стало2', 'было3': 'стало3'};
$("body").children().each(function() {
  let currentNode = $(this);
  for (const pair in replacePairs) {
     currentNode.html(currentNode.html().replace(/`${pair}`/g, `${replacePairs[pair]}`));
  }
});