How to filter keys in URLSearchParams?

Question

JavaScript

Guys, tell me pliz, there is an array of keys by which you need to filter the keys in URLSearchParams. that is, leave in URLSearchParams only those keys that are specified in the array of valid keys.
for example how to delete the key utm_delete=delete

export enum UtmType {
    UtmSource = 'utm_source',
    UtmMedium = 'utm_medium',
  }
const url = '?utm_source=stop&utm_medium=get&utm_delete=delete'
const params = new URLSearchParams(url)

Answer 1

for (const key of utm) {
    params.delete(key);
}

UPD :

const href = 'https://example.com/?user=John&some_key=1&id=3';
const url = new URL(href);
const availableKeys = ['user', 'id'];
for (const key of [...url.searchParams.keys()]) {
    if (!availableKeys.includes(key)) {
        url.searchParams.delete(key);
    }
}
console.log(url.toString()); // 'https://example.com/?user=John&id=3'