How to display the duration of an audio/video file?

Question

linux

Good afternoon. There is a task - to write a script that goes through all the files in the directory and displays the duration of the name, size and duration, if it is an audio or video file.
Everything except duration

local file1=$1;

  for file in $file1/*
  do
  if [ -f "$file" ]
  then
  for (( i=1; i <= $count; i++ ))
  do
  printf "║ "
  done
  local filesize=$(stat -c%s "$file")
  filesize=$(echo "scale=4; $filesize / 1024 / 1024" | bc)
  local dateModify=$(date +"%d.%m.%Y в %H:%M" --reference="$file")
  local time=$(ffmpeg -t -i $file)
  
  printf "╠═ ${file##*/}, ${filesize} MB, изменено ${dateModify}, \t${time}\n"
  
  fi
  done

The time variable should store the length of the media file. I'm using the ffmpeg library and obviously doing something wrong with the options.
Thank you in advance:)

Answer 1

ffprobe is more convenient for this. In one project, I define the duration in a bash script into a variable like this:

local MUSIC_LENGTH=$(ffprobe \
    -v quiet  \
    -print_format ini  \
    -show_format  \
    "$MUSIC_PCM" | grep duration | sed s/duration=//)

$MUSIC_PCM– path to the media file.