How to create a fake field in a django model?

Question

Django

There is a simple class

class Image(models.Model):
  user = models.ForeignKey(get_user_model(), on_delete=models.CASCADE)
  name = models.TextField(verbose_name="базовое имя изображения")
  base_image = models.ImageField(verbose_name="базовое изображение")
  resize_image = models.ImageField(verbose_name="изменённое изображение", blank=True, null=True)
  class Meta:
    verbose_name = "изображение"
    verbose_name_plural = "изображения"
  def __str__(self):
    return self.name

It is necessary to add calculated "fake" fields, which, if not reflected in the database, would nevertheless be perceived by django as normal models.Field, i.e. were available in the admin panel, were given by graphen without a tambourine, etc. Something like

def get_image(self) -> str:
  if self.resize_image:
    return self.resize_image
  else:
    return self.base_image
image = property(get_image)

, only working.

Answer 1

The method without parameters is normally shown in the admin panel, you don't even need to make it property https://docs.djangoproject.com/en/3.1/ref/contrib/... what's wrong with graphen, no idea.