How to correctly form an AJAX request under Fancybox 3?

Question

JavaScript

There is such a function that displays the necessary data in the jqueryui modal window:

function ShowProfile( name, url, allowedit ){
  if (dle_user_profile == name && document.getElementById('dleprofilepopup')) {$('#dleprofilepopup').dialog('open');return false;}
  dle_user_profile = name;
  dle_user_profile_link = url;
  ShowLoading('');
  $.get(dle_root + "engine/ajax/controller.php?mod=profile", { name: name, skin: dle_skin, user_hash: dle_login_hash }, function(data){
    HideLoading('');
    ShowPopupProfile( data, allowedit );
  });
  return false;
};

But I want to remake this window with FancyBox3
plugin Here is my attempt:

function ShowProfile( name, url, allowedit ){
  if (dle_user_profile == name && document.getElementById('dleprofilepopup')) {$('#dleprofilepopup').dialog('open');return false;}
  dle_user_profile = name;
  dle_user_profile_link = url;
  ShowLoading('');
  $.get(dle_root + "engine/ajax/controller.php?mod=profile", { name: name, skin: dle_skin, user_hash: dle_login_hash }, function(data){
    HideLoading('');
    
    $.fancybox.open({
       src: "data",
       type: "ajax",
       ajax: {
           settings: {
               type: "POST",
               data: {
                   name: name,
                   myparam2: "value2"
               }
           }
        }
    });
  });
  return false;
};

But for some reason it loads in the window the entire page on which I am, instead of the data transmitted by the php file
How to adapt this request correctly?