How to compare an IP address with a given mask?

Question

linux

How to compare in bash ip with a mask in my case so that ip has the address 192.168.10.*?
For example, the $ip variable is 192.168.10.5, not 127.0.0.1.

Answer 1

put ipcalc will help
but in your case
192.168.10.0/24

Answer 2

For debian there used to be such a utility www.pc-tools.net/unix/grepcidr
Maybe it will help.

Answer 3

Well, something like this, PATTERN for grep / egrep think out for your own conditions

[[email protected] ~]$ ip=192.168.10.5 
[[email protected] ~]$ mask=192.168.10.[0-9]
[[email protected] ~]$ echo $ip | egrep $mask
192.168.10.5

Answer 4

ip=192.168.10.5
fourth_octet=`echo $ip | awk -F "." '{print $4}'
echo $fourth_octet
so you get the fourth octet of the IP address, you can then compare it to anything...