How not to display an empty menu?

Question

PHP

<?php if (isset($category['children'][$i]['level3'])) {  $level3menus = $category['children'][$i]['level3']; ?>
              <ul class="level3">
                <?php foreach( $level3menus as $level3menu) {?>
                  <li><a href="<?php echo $level3menu['href']; ?>" class=""><?php echo $level3menu['name'];?></a></li>
                <?php } ?>
              </ul>
            <?php } ?>

There is such a code, it displays the third level menu in the site header (Opencart 1.5)
It works fine, but the problem is that if the 2nd level category has no children, then the 3rd level menu is still displayed, just empty

Is there any way to fix this easily by adding some condition to the code above?

Answer 1

Add !empty, but just add, do not replace isset otherwise there will be an error in the absence of completely 3 levels