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Boiling a liquid in a vacuum?
Good evening, Habrazhiteli, a question for those who understand physical processes:
1. Suppose, from a sealed vessel filled with, say, 2/3 or 1/2 water, we pump out air, thereby lowering atmospheric pressure until the moment when the water starts to boil ( environment 24 degrees Celsius)
2. We place inside this vessel a device that generates energy due to the movement of water molecules from bubbling, will the efficiency be higher than 1? After all, we don’t spend energy after pumping out air, but at the output we get energy from seething, right?
3. Does the temperature of water increase in such a vessel (the movement of molecules during bubbling) at the same ambient temperature? Wednesdays? If so, why does the temperature of t remain the same when water is removed from this vessel?
4. And the main question is, how long will it boil? Will it stop boiling, and why, if so?
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1. No contradictions.
2. And here you have a nightmare in general. Molecules are always moving. What is with boiling, what is in the absence of boiling. Therefore, your miracle device can always work at all. Of course, he will take energy not from the great nothing, but by cooling the water.
I see no point in commenting on further points.
Perpetuum mobile!!!!
4. It will boil until the vapor pressure reaches 0.029 atm (saturated vapor pressure at 24 degrees). In this case, the water will cool down a little - it will lose energy for evaporation.
Perpetuum mobile will stop....
"1. Suppose, from a sealed vessel filled with, say, 2/3 or 1/2 water, we pump out air, thereby lowering the atmospheric pressure until the water begins to boil (environment 24 degrees Celsius)."
Let's say.
"2. We put inside this vessel a device that generates energy due to the movement of water molecules from seething, will the efficiency be higher than 1?"
Steam engine? The efficiency will not exceed 1, in no case will we get more useful work than the energy spent on heating the liquid and boiling it.
"We do not spend energy after pumping out air, but at the output we get energy from seething, right?"
We expend energy on heating water or (if the boiling point is lower than the ambient temperature) on pumping out air, and later on pumping out evaporated steam.
"3. Does the temperature of water increase in such a vessel (the movement of molecules during bubbling) at the same ambient temperature? If so, why does the temperature remain the same when water is removed from this vessel?"
Rephrase the question - it's full of syntax errors so I can only guess what you meant.
"4. And the main question is actually how long will it boil? Will it stop boiling, and why, if so?"
It will stop, as the steam will very quickly increase the pressure in the vessel.
PS: https://ru.wikipedia.org/wiki/%D0%A2%D0%B5%D1%80%D...
If your thoughts lead to a violation of any of the principles of thermodynamics - the error is in your thoughts, and not in the "beginnings".
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