Android How to display different layout.xml in one ListView in a loop?

Question

Android

There is a ListView on the Activity, there is an array of data (contact sheet) that needs to be displayed in the ListView. How to display array elements differently?
contacts is a json string

contactsList = new ArrayList<HashMap<String, String>>();
        lv_contacts = (ListView) findViewById(R.id.lv_contacts);
        try {//Считаем контакты и заносим в contactsList
            mArray = new JSONArray(contacts);
            for (int i = 0; i < mArray.length(); i++) {
                JSONObject mJsonObject = mArray.getJSONObject(i);
                HashMap<String, String> map = new HashMap<String, String>();
                map.put("cid", mJsonObject.getString("cid"));
                map.put("name", mJsonObject.getString("name"));
                contactsList.add(map);
            }
        } catch (JSONException e) {
            e.printStackTrace();
        }
        ListAdapter adapter = new SimpleAdapter(
                ContactsActivity.this, contactsList, R.layout.item_contactslist,
                new String[] { "cid","name"}, new int[] { R.id.cid, R.id.name });
        lv_contacts.setAdapter(adapter);

item_contactslist.xml code

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="horizontal"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:id="@+id/list_item"
    android:gravity="center_vertical">
    <TextView
        android:id="@+id/cid"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:visibility="gone" />
    <TextView
        android:id="@+id/name"
        android:layout_width="fill_parent"
        android:layout_height="wrap_content"
        android:paddingTop="6dp"
        android:paddingLeft="6dp"
        android:textSize="17sp"
        android:textStyle="bold" />
</LinearLayout>

how to make for example every second contact a different style? Or the second display with right alignment? or with * in front of the name?
Use multiple .xml layouts? Or all in one it is possible to implement?

Answer 1

Reload adapter android.leocardz.com/multiple-layout-listview

Answer 2

Make several layouts with the necessary styles for the list element. Write your adapter for the list. In the method that gives the layout for the element, specify which one to give depending on the evenness of the element number, if it is necessary that there be alternation, for example.

Answer 3

You need a custom adapter. Something like:

private class MySimpleAdapter extends SimpleAdapter{

    public MySimpleAdapter(Context context, List<? extends Map<String, ?>> data, int resource, String[] from, int[] to) {
        super(context, data, resource, from, to);
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View v = convertView;
        if (v == null) {
            LayoutInflater vi = (LayoutInflater)getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            v = vi.inflate(R.layout. item_contactslist, null);
        }
        HashMap<String, String> item = (HashMap<String, String>) ListOfContacts.getItemAtPosition(position);
            if(item.get("name") != null){
                name.setText(item.get("name"));
            }else{
                 name.setText("NoNamed");
            }
        return v;
    }
}