Why is the variable after the regular expression empty?

S

shnicel2016-03-02 23:45:32

bash

shnicel, 2016-03-02 23:45:32

I want to cut /img_test/f15/ from here /home/admin/web/ovcvs4ds.fvds.ru/public_html/img_test/f15/f1578e58f50e5d4cb081c10a827eac71.png in this way

FINALFOLDER=$(find $CURRENT_IMAGE -regextype posix-extended -regex '\/img_test\/.*\/')
echo "$FINALFOLDER"

but everything is empty in the console, why?

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1 answer(s)

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xotkot, 2016-03-03
@shnicel

$ CURRENT_IMAGE="/home/admin/web/ovcvs4ds.fvds.ru/public_html/img_test/f15/f1578e58f50e5d4cb081c10a827eac71.png"
$ echo $CURRENT_IMAGE | grep -o -e '\/img_test\/.*\/' 
/img_test/f15/