Why is the output of echo not being written to a variable (bash)?

Question

bash

Here is the code:

for word in $allUsers; do
    tmpStr=$(echo '{"{#EMAIL}":"'$word'"}' | python -lmjson.tool)
    echo $tmpStr
done

Writes an error:

Unknown option: -l
usage: python [option] ... [-c cmd | -m mod | file | -] [arg] ...
Try `python -h' for more information.

Didn't notice the typo, thanks DevMan. Before that, I tested the line separately, everything was good. And when copying, something is not pressed. Vi doesn't lend itself well to me. Now the line worked fine, but some problems with formatting appeared along the way. The conclusions differ
echo '{"{#EMAIL}":"'$word'"}' | python -mjson.tool
echo '{"{#EMAIL}":"'$word'"}' | python -mjson.tool

{
(indent here)"{#EMAIL}": "[email protected]"
}

and

tmpStr+=$(echo '{"{#EMAIL}":"'$word'"}' | python -mjson.tool)
echo $tmpStr

The conclusion is:

{ "{#EMAIL}": "[email protected]" }

Is that possible?

Answer 1

I do
IP=$(ifconfig | grep inet | grep -v inet6 | grep -v 127.0.0.1 | cut -d: -f2 | awk '{printf $1"\n"}') | echo "RPAFproxy_ips 127.0.0.1 $IP"