Why is the code not executed after calling the promise and the process does not die?

Question

JavaScript

const find = async function (){
  try{
    console.log(await Model.findOne())
    console.log('after find');
  }
  catch (e){
    console.log('find err = ' + e); // не выводится т.к. нет ошибок
  }
}

find()
.then(()=>{console.log('then')})

console.log('END'); // Не выводится и процесс не завершается

Answer 1

Because Model.findOne() returns a promise that is never fulfilled. As a result, the await operator waits for this promise forever. Well, let him wait, all of a sudden, the promise will still someday be fulfilled, and the find () function will continue, and after it the script will end.