Why is php code executed in js code (session)?

S

Space Around2018-11-16 00:51:00

PHP

Space Around, 2018-11-16 00:51:00

When the site is launched, the login is equal to guest, if you enter user1 and log in, everything seems to be ok, but if you restart the site 2 times, then the code will be executed, as if you clicked on exit, although you didn’t click anywhere and the login will become guest1. Why is php code being executed when it shouldn't be executing
HTML

<?php
include_once "php/session.php";
?>

<!DOCTYPE html>
<html>
    <head>
        <meta charset="utf-8">
        <meta http-equiv="X-UA-Compatible" content="IE=edge">
        <meta name="viewport" content="width=device-width, initial-scale=1">
        <meta http-equiv="Content-Type" content="text/html; charset=utf-8">
        <title>Testing</title>

        <link rel="stylesheet" href="https://use.fontawesome.com/releases/v5.3.1/css/all.css" integrity="sha384-mzrmE5qonljUremFsqc01SB46JvROS7bZs3IO2EmfFsd15uHvIt+Y8vEf7N7fWAU" crossorigin="anonymous">
        <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font-awesome/4.7.0/css/font-awesome.min.css">
        <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/css/bootstrap.min.css" integrity="sha384-MCw98/SFnGE8fJT3GXwEOngsV7Zt27NXFoaoApmYm81iuXoPkFOJwJ8ERdknLPMO" crossorigin="anonymous">
        <link href="https://fonts.googleapis.com/icon?family=Material+Icons" rel="stylesheet">
        <script src="https://code.jquery.com/jquery-3.3.1.slim.min.js" integrity="sha384-q8i/X+965DzO0rT7abK41JStQIAqVgRVzpbzo5smXKp4YfRvH+8abtTE1Pi6jizo" crossorigin="anonymous"></script>
        <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.14.3/umd/popper.min.js" integrity="sha384-ZMP7rVo3mIykV+2+9J3UJ46jBk0WLaUAdn689aCwoqbBJiSnjAK/l8WvCWPIPm49" crossorigin="anonymous"></script>
        <script src="https://stackpath.bootstrapcdn.com/bootstrap/4.1.3/js/bootstrap.min.js" integrity="sha384-ChfqqxuZUCnJSK3+MXmPNIyE6ZbWh2IMqE241rYiqJxyMiZ6OW/JmZQ5stwEULTy" crossorigin="anonymous"></script>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <style>

        </style>
    </head>
    <body>

        <input type="text" id="login">

        <button id="btn" onclick="singin();">Sign In</button>

        <button id="btn" onclick="singout();">Sign Out</button>

        <p id="login_enter"></p>

        <script>
        var str = '<?php echo $_SESSION['login'];?>';

        document.getElementById("login_enter").innerHTML = str;

        function singin () {
            var login = document.getElementById('login').value;

            jQuery.ajax({
                url:     "php/server.php",
                type:     "POST",
                dataType: "html",
                data: "login="+login,
                success: function(response) {

                    document.getElementById("login_enter").innerHTML = response;

                },
                error: function(response) {

                }
            });

        }

        function singout () {
            <?php  $_SESSION['login'] = "guest1"?>
            str = '<?php echo $_SESSION['login'];?>';
            document.getElementById("login_enter").innerHTML = str;
            console.log("exit");
        }

        </script>
    </body>
</html>

php server

<?php
require "session.php";

$login = "";

$FORM['login'] = "";

if (isset($_POST['login'])) $FORM['login'] = htmlspecialchars($_POST['login']);

$login = $FORM['login'];

if ($login == "user1") {
    $_SESSION['login'] = "user1";
    echo   $_SESSION['login'];

} else {
    echo "Такого пользователя нету";
}

?>

PHP session

<?php
session_start();

if (!isset($_SESSION['login'])) {
  $_SESSION['login'] = "guest";
}
 ?>

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1 answer(s)

A

Antony Tkachenko, 2018-11-16
@LemonFox

$_SESSION['login'] = "guest1"
You are overwriting the session