Why is bot.register_next_step_handler not working?

Question

Python

The code should send a message

Enter *percentage* you want to set

and wait for the percentage itself, but he does not survive anything and instead of the percentage sets just the same message that he himself sent

Enter *percentage* you want to set

How to solve it?

def izmproc(call, user_type, user_id):
      global a1
      a1 = user_id
      mess = database.с_message(user_id)
      code = database.c_code(user_id)
      chat_id = call.message.chat.id
      code2 = str(chat_id)[:5]
      with sqlite3.connect("evidence.db") as con:
        cur = con.cursor()
        result = cur.execute('SELECT * FROM `c` WHERE `id` = ?', (user_id,)).fetchall()
        for row in result:
          username2 = repl(row[3])
      try:
        if (code2 == code) or (call.message.chat.id == support) or (call.message.chat.id == admin):

          message = bot.send_message(chat_id, f" Введите *процент* который хотите установить [{row[4]}](https://t.me/{row[3]})", parse_mode="Markdown", disable_web_page_preview=True)
          bot.register_next_step_handler(message, proc_c(call, a1))
      except Exception as e:
        print(e)

def proc_c(call, argument):
  user_id = argument
  mess = database.c_message(user_id)
  code = database.c_code(user_id)
  chat_id = call.message.chat.id
  code2 = str(chat_id)[:5]
  try:
    if (code2 == code) or (call.message.chat.id == support) or (call.message.chat.id == admin):
      result = database.user_update_f(user_id, call.message.text)
      if (result == 1):
        bot.send_message(call.message.chat.id, f' Процент  *изменен*\nНовый процент: {database.user_f(user_id)}', parse_mode="Markdown")
      if (result == 2):
        bot.send_message(call.message.chat.id, f' *Ошибка*', parse_mode="Markdown")
    else:
      bot.send_message(call.message.chat.id, f' *Ошибка*', parse_mode="Markdown")
  except Exception as e:
    print(e)

Answer 1

bot.register_next_step_handler(message, proc_c(call, a1))

when you call register_next_step_handler , you also call the proc_c function , and you need not to call it, but pass it as a parameter.
The parameters with which the passed function should be called must come as separate parameters after the same function

bot.register_next_step_handler(message, proc_c, call, a1)