Why doesn't it display d values ​​correctly?

Question

C++ / C#

#include <stdio.h>
#pragma warning(disable : 4996)
int main() {
  unsigned char a[81], perm[256], g[81], d = 0, n = 0;
  for (int f = 0; f < 81; f++) {
    scanf("%[^\n]d", &a);
  }
  int f = 0;
  while (a[f] != '\0') {
    n++; f++;
  }
  for (int b = 0; b < 256; b++) {
    perm[b] = b;
    for (int c = 0; c < n; c++) {
      if (a[c] == perm[b]) {
        g[c] = perm[b];
      }
    }
  }
  for (int c = 0; c < n; c++) {
    if (g[c] == g[c + 1]) {
      d++;
    }
    else d = 1;
    //printf(" %d ", g[c]);
    printf(" %c=%d\n ", g[c], d);
  }

}

Answer 1

Are you seriously suggesting that we understand what goes wrong in an algorithm that has no input and no description? And even with unreadable code?

Answer 2

Not a single comment.
Who will be interested in understanding this mess? The debugger is in the teeth - and trace the program step by step, tracking the counters.

Answer 3

Apparently it needs to

for (int c = 0; c < n; c++) {
    if (g[c] == g[c + 1]) {
      d++;
      continue;
    }
    else d = 1;
    //printf(" %d ", g[c]);
    printf(" %c=%d\n ", g[c], d);
  }

Answer 4

%d is an int and you are passing unsigned char.